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SAT R&W Command of Evidence (Hard) — Drill 30

Drill 30 ยท Reading & Writing ยท Hard Command of Evidence

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Drill 30 — current you are here

About This Drill

SAT R&W Command of Evidence (Hard) — Drill 30 is a Reading & Writing practice drill covering Hard Command of Evidence. It contains 5 original questions created by Brian Stewart, a Barron's test prep author with over 20 years of tutoring experience.

A lake does not mix top to bottom all year; warm and cold layers form, hold, and break down, and that layering shapes what lives where. These items ask which reading or watershed fact decides a dispute. The two data items, a table and a line graph, are set up to be read for a contrast between conditions. The quotation item presents short classroom passages written for a study of lake science.

Questions & Explanations

Table: conditions at four depths in the lake

Table: conditions at four depths in the lake

DepthDissolved oxygenTemperature2 m8.5 mg/L21°C6 m4.1 mg/L14°C8 m6.2 mg/L13°C10 m1.5 mg/L9°C

A cold-water fish can settle only where two conditions hold together: the water must carry at least 5 milligrams of dissolved oxygen per liter, and it must be no warmer than 15 °C. A depth that meets only one of these is unsuitable. The table reports, for four depths in a stratified lake, the dissolved oxygen and the temperature measured at each.

Question 1. Based on the table, which depth meets both conditions the cold-water fish needs?

  • A) 2 meters
  • B) 6 meters
  • C) 10 meters
  • D) 8 meters ✓

Explanation: Correct: The 8-meter depth is the only one to satisfy both conditions: its dissolved oxygen is 6.2 milligrams per liter (at least 5) and its temperature is 13 degrees Celsius (no warmer than 15). Both conditions hold at once. A: At 2 meters the oxygen is ample at 8.5 milligrams per liter, but the water is 21 degrees Celsius, well above the 15-degree limit, so it fails the temperature condition. B: At 6 meters the temperature is a suitable 14 degrees Celsius, but the oxygen has fallen to 4.1 milligrams per liter, below the 5-milligram floor, so it fails the oxygen condition. C: At 10 meters the water is cold at 9 degrees Celsius but its oxygen is only 1.5 milligrams per liter, far below the floor, so it fails on oxygen.

Text 1

Each autumn a lake's long-standing warm-over-cold layering breaks down and the water mixes top to bottom, an event called turnover. One account credits the season's strengthening winds, which stir the surface hard enough to overturn the layers. Another credits the cooling air, which chills the surface water until it grows dense enough to sink on its own. Both arrive in autumn together, so a limnologist looks for a year that pulls them apart.

Question 2. Which finding, if true, would most strongly support the cooling account over the wind account?

  • A) Turnover each autumn is reliably followed within a week or two by a noticeable surge of algae growth across the lake's sunlit surface waters.
  • B) In a year when autumn winds stayed unusually weak, turnover still arrived on schedule once the surface water had chilled to match the depths. ✓
  • C) The lake sits in a wide, open basin with low surrounding ground, leaving its surface exposed to wind sweeping across it from nearly every direction.
  • D) The lake's surface water reaches its warmest point in late summer, a few weeks before the autumn turnover begins to break the layering down.

Explanation: Correct: Turnover occurred once cooling erased the density difference between surface and depths, even without unusually strong winds, so the result favors cooling as the trigger over strengthened winds as the main cause. Wind still supplies mixing energy in a real lake, but here it was the loss of the density barrier, not a burst of wind, that let the lake overturn on schedule. A: An algae surge after turnover is a consequence of mixing, not a clue to whether wind or cooling caused it. C: An open, wind-exposed basin would if anything support the wind account; it does not favor cooling. D: That the surface is warmest weeks before turnover sets the seasonal scene but does not separate cooling from wind as the trigger.

Text 1

For a study unit on lake science, a student is given four short passages written for the class about lake stratification. The student argues that one passage supports a specific claim: that the lake's middle transition layer, where temperature drops sharply with depth, acts as a barrier that keeps the warm surface and cold bottom waters from mixing through the summer.

Question 3. Which passage most directly supports the student's claim about the middle transition layer acting as a barrier to mixing?

  • A) "The surface layer warms first as spring advances, and by the height of midsummer it stands several degrees warmer than the still water lying far below it, the two no longer trading heat freely across the depth of the lake."
  • B) "Oxygen produced by plants near the sunlit surface is steadily consumed by the slow decay of organic matter settling into the sediments at the bottom of the deeper lakes, which can leave those depths starved of it by late summer."
  • C) "Across the narrow mid-depth band, water just above and just below differs enough in density that turbulence crossing the band is strongly damped, so the upper and lower layers remain largely separate until fall." ✓
  • D) "Wind blowing across a broad lake can push surface water toward the downwind shore, tilting the warm layer."

Explanation: Correct: The claim is that the steep mid-depth band blocks mixing between the upper and lower water. The keyed passage captures that without naming it outright: a density difference across the narrow band damps the turbulence that would cross it, so the layers stay separate until fall -- which is what acting as a barrier to mixing means. A: This explains why the surface ends up warmer than the depths, setting up the layering but not stating that the middle layer blocks mixing. B: This is about where oxygen is made and used up, a separate point that says nothing about a barrier to vertical mixing. D: Wind tilting the warm layer describes a surface disturbance, not the transition layer resisting mixing between top and bottom.

Text 1

A cold, sediment-laden stream enters a stratified lake at the surface. A limnologist proposes that because the inflow is colder and carries enough suspended sediment to be denser than the lake water at every depth, it should plunge below the surface layer and travel along the bottom rather than spreading across the top. If that is right, the proposal predicts that a tracer dye added to the stream should turn up in the lake's deep water rather than staying near the surface. The team runs the test.

Question 4. Which result would best fit the prediction that follows from the denser-inflow proposal?

  • A) Dye added to the inflow disappears from the surface near the stream mouth and reappears in samples drawn from near the lake bottom. ✓
  • B) Dye added to the incoming stream spreads in a thin film across the warm surface layer and lingers there for days.
  • C) Dye added to the incoming stream stays plainly detectable in the moving stream water itself right up to the point where the stream finally meets the open lake.
  • D) Dye added to the incoming stream gradually fades from view over time as it is steadily diluted into the much larger surrounding volume of the whole lake.

Explanation: Correct: The proposal predicts the dense inflow dives beneath the surface and runs deep. Dye that vanishes from the surface at the stream mouth and shows up in bottom samples traces exactly that plunging path, fitting the prediction. B: Dye filming across the warm surface and staying is the opposite of the prediction; it is what a buoyant, less dense inflow would do. C: Dye still in the stream before it reaches the lake only shows the tracer was present; it says nothing about where the inflow goes once inside. D: Dye fading by dilution could happen at any depth and tells you the lake is large, not whether the inflow sank or spread.

Text 1
02468101214168121620Water temperature (degrees C)Depth (meters)

A probe lowered through a stratified lake records water temperature at each depth, from the warm surface down into the cold deep water. The resulting profile is plotted as temperature against depth. Researchers want to locate the transition layer -- the depth band where temperature falls most steeply with depth, separating the near-uniform warm surface water above from the near-uniform cold water below.

Question 5. Which statement best identifies where the profile marks the transition layer?

  • A) Temperature on the profile is highest right at the surface and lowest at the greatest depth the probe reached.
  • B) Temperature changes only a little from reading to reading as the probe passes down through the warm, well-mixed water near the lake's surface.
  • C) Over a narrow band at middle depth the temperature drops far more steeply with depth than it does above or below that band. ✓
  • D) Temperature changes only a little from reading to reading as the probe passes down through the cold, near-uniform water close to the lake's bottom.

Explanation: Correct: The transition layer is the band where temperature changes most over a short interval of depth. Because temperature is on the horizontal axis and depth on the vertical one, that band shows up as the middle stretch where the curve swings sharply toward the cold (left) side as the probe descends just a few meters. The more upright stretches near the surface and the bottom are layers where temperature barely changes with depth. A: Warmest at top and coldest at the bottom is true of the whole profile but only states the end points; it does not locate the band of steepest change. B: Little change through the surface water describes the warm layer above the transition, not the steep band itself. D: Little change through the bottom water describes the cold layer below the transition, again not the steep band that defines it.