📐 SAT
📝 ACT
🎓 AP Exams
About Contact Blog Privacy Policy

AP Biology — Unit 3 — Energy, ATP & Free Energy — Drill 8

Drill 8 ·

0 / 5
0/5 correct

Nice work!

Review your answers above to learn from any mistakes.

← More Drills
←
Previous drill
Drill 7
Next drill
Drill 9
→
More AP Bio drills
Drill 1 5 questions → Drill 2 5 questions → Drill 3 5 questions → Drill 4 5 questions → Drill 5 5 questions → Drill 6 5 questions → Drill 7 5 questions →
Drill 8 — current you are here
Drill 9 5 questions → Drill 10 5 questions → Drill 11 5 questions → Drill 12 5 questions → Drill 13 5 questions → Drill 14 5 questions → Drill 15 5 questions → Drill 16 5 questions → Drill 17 5 questions → Drill 18 5 questions → Drill 19 5 questions → Drill 20 5 questions → Drill 21 5 questions → Drill 22 5 questions → Drill 23 5 questions → Drill 24 5 questions → Drill 25 5 questions → Drill 26 5 questions → Drill 27 5 questions → Drill 28 5 questions → Drill 29 5 questions → Drill 30 5 questions → Drill 31 5 questions → Drill 32 5 questions → Drill 33 5 questions → Drill 34 5 questions → Drill 35 5 questions → Drill 36 5 questions → Drill 37 5 questions →

About This Drill

AP Biology — Unit 3 — Energy, ATP & Free Energy — Drill 8 is a practice drill. It contains 5 original questions created by Brian Stewart, a Barron's test prep author with over 20 years of tutoring experience.

Practice interpreting photosynthesis data with this AP Biology drill. You will analyze the relationship between light intensity and net oxygen production in an aquatic plant, identify the light compensation point, explain why photosynthetic rate plateaus at high light intensity, calculate gross photosynthesis from net O2 data, and predict how changing CO2 concentration would affect the rate of photosynthesis at light saturation.

Passage

A research team investigated the effect of light intensity on net oxygen production in the aquatic plant Elodea canadensis. Sealed chambers containing equal masses of plant tissue were exposed to different light intensities for 30-minute intervals at a constant temperature of 22 degrees Celsius and constant CO2 concentration. Net oxygen production (micromoles O2 per gram of plant tissue per minute) was measured using a dissolved oxygen probe at the end of each interval. Negative values indicate net oxygen consumption. All other variables, including water temperature, pH, and dissolved CO2, were held constant throughout the experiment. Observed net O2 production at each light intensity: Light intensity 0 lux: Net O2 = -3.2 micromol/g/min Light intensity 500 lux: Net O2 = 0.0 micromol/g/min Light intensity 1,000 lux: Net O2 = +4.1 micromol/g/min Light intensity 2,000 lux: Net O2 = +7.8 micromol/g/min Light intensity 4,000 lux: Net O2 = +8.1 micromol/g/min

Questions in This Drill

  1. At 0 lux light intensity, the net oxygen production is -3.2 micromol/g/min. Which of the following best explains why the value is negative under these conditions?
  2. The light compensation point is the light intensity at which the rate of gross photosynthesis exactly equals the rate of cellular respiration, resulting in no net change in oxygen. Based on the data, which of the following correctly identifies the light compensation point and explains its significance?
  3. The data show that net oxygen production increases substantially between 500 and 2,000 lux, but increases only slightly between 2,000 and 4,000 lux (from 7.8 to 8.1 micromol/g/min). Which of the following best explains why increasing light intensity beyond 2,000 lux produces diminishing gains in oxygen production?
  4. Using the 0 lux data point, a student claims that the gross rate of photosynthesis at 500 lux is 3.2 micromol O2/g/min. Which of the following best evaluates this claim?
  5. The experiment was conducted at a constant CO2 concentration. If the same experiment were repeated with CO2 concentration doubled while all other conditions remained identical, which of the following best predicts the effect on net oxygen production at 4,000 lux?