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SAT Math: Scatterplots and Lines of Best Fit (Drill 3)

Drill 3 · Math · Scatterplots and Lines of Best Fit

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About This Drill

SAT Math: Scatterplots and Lines of Best Fit (Drill 3) is a Math practice drill covering Scatterplots and Lines of Best Fit. It contains 5 original questions created by Brian Stewart, a Barron's test prep author with over 20 years of tutoring experience.

SAT scatterplot questions cover comparing linear and exponential models, making predictions by extrapolating from lines of best fit, interpreting slope as a rate of change in context, and calculating and interpreting residuals for individual data points.

Questions & Explanations

Question 1. Which of the following is true about the values of 3x and 4x + 1 for x > 0?

  • A) For all x > 0, it is true that 3x < 4x + 1.
  • B) For all x > 0, it is true that 3x > 4x + 1.
  • C) There is a constant c such that if 0 < x < c, then 3x < 4x + 1, but if x > c, then 3x > 4x + 1. ✓
  • D) There is a constant c such that if 0 < x < c, then 3x > 4x + 1, but if x > c, then 3x < 4x + 1.

Explanation: At x = 0, 30 = 1 and 4(0) + 1 = 1, so they are equal. At x = 1, 31 = 3 and 4(1) + 1 = 5, so 3x < 4x + 1. At x = 2, 32 = 9 and 4(2) + 1 = 9, so they are equal again. At x = 3, 33 = 27 and 4(3) + 1 = 13, so 3x > 4x + 1. The exponential starts below the linear function, then overtakes it. There is a constant c = 2 where the crossover occurs: for 0 < x < 2, 3x < 4x + 1, and for x > 2, 3x > 4x + 1.

Text 1
Monthly Revenue for a New Business
MonthRevenue ($)
14,200
25,800
37,100
49,000
510,400
The line of best fit is y = 1,550x + 2,500.

Question 2. Based on the line of best fit, what is the predicted revenue for month 8?

  • A) $12,400
  • B) $14,900 ✓
  • C) $15,500
  • D) $17,200

Explanation: Substitute x = 8: y = 1,550(8) + 2,500 = 12,400 + 2,500 = 14,900. Choice A (12,400) omits the y-intercept. Choice C (15,500) may result from a computation error. Note that this is an extrapolation beyond the data, so the prediction assumes the linear trend continues.

Question 3. A biologist models the concentration of a chemical in a lake using the equation C(t) = 120(0.85)t, where C is the concentration in parts per million and t is the number of weeks since a cleanup began. Which of the following best describes what the model predicts?

  • A) The concentration decreases by 0.85 parts per million each week.
  • B) The concentration decreases by 85% each week.
  • C) The concentration decreases by 15% each week. ✓
  • D) The concentration increases by 15% each week.

Explanation: In the model C(t) = 120(0.85)t, the base 0.85 represents the fraction retained each week. Since 0.85 = 1 − 0.15, the concentration retains 85% of its previous value each week, meaning it decreases by 15% per week. Choice A confuses the base with a constant decrease. Choice B reverses the interpretation, the concentration retains 85%, it doesn't lose 85%.

Question 4. A delivery company records the total fuel cost, in dollars, for trips of various distances. The line of best fit is y = 0.38x + 12.50, where x is the distance in miles and y is the fuel cost in dollars. Which of the following is the best interpretation of 0.38 in this context?

  • A) The minimum fuel cost for any trip is $0.38.
  • B) For each additional mile driven, the fuel cost increases by $0.38. ✓
  • C) For each additional dollar spent on fuel, the distance increases by 0.38 miles.
  • D) The average total fuel cost per trip is $0.38.

Explanation: The slope of a line of best fit represents the change in y for each one-unit increase in x. Here, x is distance in miles and y is fuel cost in dollars. So the slope of 0.38 means that for each additional mile driven, the predicted fuel cost increases by $0.38. Choice A describes a minimum, not a rate of change. Choice C reverses the x and y relationship.

Text 1
Student Study Hours and Test Scores
Hours Studied (x)Test Score (y)
162
271
374
485
588
690
The line of best fit is y = 5.6x + 58.5.

Question 5. For which value of x is the residual (actual − predicted) the most negative?

  • A) x = 1 ✓
  • B) x = 2
  • C) x = 3
  • D) x = 5

Explanation: Calculate the residual (actual − predicted) for each choice. At x = 1: predicted = 5.6(1) + 58.5 = 64.1, residual = 62 − 64.1 = −2.1. At x = 2: predicted = 5.6(2) + 58.5 = 69.7, residual = 71 − 69.7 = +1.3. At x = 3: predicted = 5.6(3) + 58.5 = 75.3, residual = 74 − 75.3 = −1.3. At x = 5: predicted = 5.6(5) + 58.5 = 86.5, residual = 88 − 86.5 = +1.5. The most negative residual is −2.1 at x = 1, meaning the actual score was 2.1 points below the line of best fit. Choice C (x = 3) also has a negative residual (−1.3) but it is less negative than at x = 1.