Drill 3 · Math · Scatterplots and Lines of Best Fit
SAT Math: Scatterplots and Lines of Best Fit (Drill 3) is a Math practice drill covering Scatterplots and Lines of Best Fit. It contains 5 original questions created by Brian Stewart, a Barron's test prep author with over 20 years of tutoring experience.
SAT scatterplot questions cover comparing linear and exponential models, making predictions by extrapolating from lines of best fit, interpreting slope as a rate of change in context, and calculating and interpreting residuals for individual data points.
Question 1. Which of the following is true about the values of 3x and 4x + 1 for x > 0?
Explanation: At x = 0, 30 = 1 and 4(0) + 1 = 1, so they are equal. At x = 1, 31 = 3 and 4(1) + 1 = 5, so 3x < 4x + 1. At x = 2, 32 = 9 and 4(2) + 1 = 9, so they are equal again. At x = 3, 33 = 27 and 4(3) + 1 = 13, so 3x > 4x + 1. The exponential starts below the linear function, then overtakes it. There is a constant c = 2 where the crossover occurs: for 0 < x < 2, 3x < 4x + 1, and for x > 2, 3x > 4x + 1.
| Month | Revenue ($) |
|---|---|
| 1 | 4,200 |
| 2 | 5,800 |
| 3 | 7,100 |
| 4 | 9,000 |
| 5 | 10,400 |
Question 2. Based on the line of best fit, what is the predicted revenue for month 8?
Explanation: Substitute x = 8: y = 1,550(8) + 2,500 = 12,400 + 2,500 = 14,900. Choice A (12,400) omits the y-intercept. Choice C (15,500) may result from a computation error. Note that this is an extrapolation beyond the data, so the prediction assumes the linear trend continues.
Question 3. A biologist models the concentration of a chemical in a lake using the equation C(t) = 120(0.85)t, where C is the concentration in parts per million and t is the number of weeks since a cleanup began. Which of the following best describes what the model predicts?
Explanation: In the model C(t) = 120(0.85)t, the base 0.85 represents the fraction retained each week. Since 0.85 = 1 − 0.15, the concentration retains 85% of its previous value each week, meaning it decreases by 15% per week. Choice A confuses the base with a constant decrease. Choice B reverses the interpretation, the concentration retains 85%, it doesn't lose 85%.
Question 4. A delivery company records the total fuel cost, in dollars, for trips of various distances. The line of best fit is y = 0.38x + 12.50, where x is the distance in miles and y is the fuel cost in dollars. Which of the following is the best interpretation of 0.38 in this context?
Explanation: The slope of a line of best fit represents the change in y for each one-unit increase in x. Here, x is distance in miles and y is fuel cost in dollars. So the slope of 0.38 means that for each additional mile driven, the predicted fuel cost increases by $0.38. Choice A describes a minimum, not a rate of change. Choice C reverses the x and y relationship.
| Hours Studied (x) | Test Score (y) |
|---|---|
| 1 | 62 |
| 2 | 71 |
| 3 | 74 |
| 4 | 85 |
| 5 | 88 |
| 6 | 90 |
Question 5. For which value of x is the residual (actual − predicted) the most negative?
Explanation: Calculate the residual (actual − predicted) for each choice. At x = 1: predicted = 5.6(1) + 58.5 = 64.1, residual = 62 − 64.1 = −2.1. At x = 2: predicted = 5.6(2) + 58.5 = 69.7, residual = 71 − 69.7 = +1.3. At x = 3: predicted = 5.6(3) + 58.5 = 75.3, residual = 74 − 75.3 = −1.3. At x = 5: predicted = 5.6(5) + 58.5 = 86.5, residual = 88 − 86.5 = +1.5. The most negative residual is −2.1 at x = 1, meaning the actual score was 2.1 points below the line of best fit. Choice C (x = 3) also has a negative residual (−1.3) but it is less negative than at x = 1.