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SAT Math: Exponentials and Radicals (Drill 1)

Drill 1 · Math · Exponentials and Radicals

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About This Drill

SAT Math: Exponentials and Radicals (Drill 1) is a Math practice drill covering Exponentials and Radicals. It contains 5 original questions created by Brian Stewart, a Barron's test prep author with over 20 years of tutoring experience.

Exponential functions model growth and decay. These questions cover interpreting exponential equations, simplifying expressions with exponents and radicals, and solving equations with fractional or negative exponents.

Questions & Explanations

Question 1. The value of a car, in dollars, t years after purchase is modeled by V(t) = 25,000(0.85)t. What does 0.85 represent in this context?

  • A) The car loses $0.85 in value each year.
  • B) The car retains 85% of its original value after t years for the function shown.
  • C) The car retains 85% of its value from one year to the next. ✓
  • D) The car's value increases by 85% each year.

Explanation: In the model V(t) = 25,000(0.85)t, the base 0.85 is the factor by which the value is multiplied each year. Since 0.85 = 1 − 0.15, the car retains 85% of its value (or loses 15%) from one year to the next. Choice B is incorrect because the 85% retention applies year over year, not relative to the original value after t years.

Question 2. What is the value of (23)(24)?

  • A) 64
  • B) 128 ✓
  • C) 256
  • D) 4,096

Explanation: When multiplying powers with the same base, add the exponents: 23 × 24 = 27 = 128. Choice A (64 = 26) adds incorrectly. Choice D (4,096 = 212) multiplies the exponents instead of adding them.

Question 3. If 3x = 81, what is the value of x?

  • A) 2
  • B) 3
  • C) 3.5
  • D) 4 ✓

Explanation: Express 81 as a power of 3: 81 = 34. Since 3x = 34, x = 4.

Question 4. The population of a town is modeled by P(t) = 500(1.03)t, where t is the number of years since 2010. What was the population of the town in 2010?

  • A) 500 ✓
  • B) 515
  • C) 530
  • D) 1,030

Explanation: In 2010, t = 0. P(0) = 500(1.03)0 = 500(1) = 500. Any number raised to the zero power equals 1, so the initial population is simply the coefficient, 500.

Question 5. Which of the following is equivalent to √72?

  • A) 4√3
  • B) 3√8
  • C) 6√2
  • D) 8√3

Explanation: Factor 72 into a perfect square times another factor: 72 = 36 × 2. Then √72 = √36 × 2 = √36 × √2 = 6√2.