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SAT Math: Circles, Arcs, and Angles (Drill 1)

Drill 1 · Math · Circles, Arcs, and Angles

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About This Drill

SAT Math: Circles, Arcs, and Angles (Drill 1) is a Math practice drill covering Circles, Arcs, and Angles. It contains 5 original questions created by Brian Stewart, a Barron's test prep author with over 20 years of tutoring experience.

Circle questions on the SAT cover the standard equation of a circle, arc length, sector area, central and inscribed angles, and the relationship between a circle's radius, diameter, and circumference.

Questions & Explanations

Question 1. A circle has a radius of 10 centimeters. What is the length of an arc intercepted by a central angle of 72°?

  • A) 2π cm
  • B) 4π cm ✓
  • C) 10π cm
  • D) 20π cm

Explanation: Arc length = (θ/360)(2πr) = (72/360)(2π × 10) = (1/5)(20π) = 4π cm. The fraction 72/360 simplifies to 1/5.

Question 2. A circle has a radius of 6 inches. What is the area of a sector with a central angle of 90°?

  • A) 6π square inches
  • B) 3π square inches
  • C) 12π square inches
  • D) 9π square inches ✓

Explanation: Sector area = (θ/360)(πr²) = (90/360)(π × 36) = (1/4)(36π) = 9π square inches. A 90° sector is one-quarter of the full circle.

Question 3. The equation x² + y² − 8x + 6y = 0 represents a circle in the xy-plane. What is the center of the circle?

  • A) (4, −3) ✓
  • B) (−4, 3)
  • C) (8, −6)
  • D) (4, 3)

Explanation: Complete the square for both x and y. Group: (x² − 8x) + (y² + 6y) = 0. Complete: (x² − 8x + 16) + (y² + 6y + 9) = 0 + 16 + 9. Simplify: (x − 4)² + (y + 3)² = 25. The center is (4, −3) and the radius is 5.

Question 4. A central angle in a circle measures 140°. What is the measure of an inscribed angle that intercepts the same arc?

  • A) 140°
  • B) 280°
  • C) 70° ✓
  • D) 35°

Explanation: An inscribed angle is always half the central angle that intercepts the same arc. Inscribed angle = 140° ÷ 2 = 70°. This is the inscribed angle theorem.

Question 5. A circle has a circumference of 16π. What is the area of the circle?

  • A) 32π
  • B) 64π ✓
  • C) 128π
  • D) 256π

Explanation: From the circumference: 2πr = 16π, so r = 8. Area = πr² = π(8)² = 64π.